Respuesta :

1 mole of any substance has [tex]6.02*10^{23} particles. So, 1.39 mol N_{2}O_{5} have [/tex]

[tex]1.39 mol * \frac{6.02*10^{23}}{1 mol} =8.37*10^{23} molecules[/tex]

Explanation:

According to Avogadro's number, it is known that there are [tex]6.023 \times 10^{23}[/tex] atoms present in 1 mole of a substance.

Therefore, molecules or atoms present in 1.39 moles will be as follows.

             No. of atoms = no. of moles × Avogadro's number

                                    = [tex]1.39 moles \times 6.023 \times 10^{23}\text{atoms/mol}[/tex]

                                    = [tex]8.37 \times 10^{23}[/tex] atoms

Thus, we can conclude that there are [tex]8.37 \times 10^{23}[/tex] atoms of dinitrogen pentoxide in 1.39 moles.