Pammie123cakess
Pammie123cakess
04-06-2014
Mathematics
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how do I solve (3+i)(3-i)
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kate200468
kate200468
04-06-2014
[tex] (3+i)(3-i)=3(3-i)+i(3-i)=9-3i+3i-i^2=9-(-1)=\\\\=9+1=10[/tex]
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kayt91
kayt91
05-06-2014
(3+I)(3-1)
-i^2+9=0
-I^2=-9
I^2=9
i= + or - 3
Answer Link
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