Respuesta :

dumbcats
if spring constant is doubled, the mass on spring will be doubled as well. according to this formula, F=ke
k stands for spring constant and e stands for the length extended

Answer:

T' = T / sqrt 2

Explanation:

According to the formula of time period of a loaded spring

[tex]T = 2\pi \sqrt{\frac{m}{k}}[/tex]      .... (1)

where, m is the mass on the spring and k be the spring constant.

Here we observe that the time period is inversely proportional to the square root of the spring constant.

If the spring constant is doubled then the time period is

[tex]T' = 2\pi \sqrt{\frac{m}{2k}}[/tex]     ....(2)

Dividing equation (2) by equation (1), we get

T' = T / sqrt 2